-8+13x^2=0

Solution for -8+13x^2=0 equation:

-8+13x^2=0

a = 13; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·13·(-8)
Δ = 416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{416}=\sqrt{16*26}=\sqrt{16}*\sqrt{26}=4\sqrt{26}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{26}}{2*13}=\frac{0-4\sqrt{26}}{26}
=-\frac{4\sqrt{26}}{26}
=-\frac{2\sqrt{26}}{13}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{26}}{2*13}=\frac{0+4\sqrt{26}}{26}
=\frac{4\sqrt{26}}{26}
=\frac{2\sqrt{26}}{13}
$